Answer:
The correct approach is "-2.67 kJ/mole". A further solution is described below.
Explanation:
The given values are:
No. of moles,
= 5.60 mol
Substance releases,
ΔH = 14.9 kJ
Now,
The ΔH in terms of kJ/mol will be:
= [tex]\frac{\Delta H}{5.60}[/tex]
On putting the given values of ΔH, we get
= [tex]\frac{-14.9}{5.60}[/tex]
= [tex]-2.67 \ kJ/mole[/tex]
