Answer:
[tex]\frac{116}{159} = 0.7296[/tex] probability that a randomly chosen applicant has over 10 years of experience, given that the applicant has a graduate degree.
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which
P(B|A) is the probability of event B happening, given that A happened.
[tex]P(A \cap B)[/tex] is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Has a graduate degree.
Event B: Has over 10 years of experience.
Out of 469 applicants for a job, 159 have over 10 years of experience and 116 have over 10 years of experience and have a graduate degree.
This means that:
[tex]P(A) = \frac{159}{469}[/tex]
[tex]P(A \cap B) = \frac{116}{469}[/tex]
Desired probability:
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{\frac{116}{469}}{\frac{159}{469}} = \frac{116}{159} = 0.7296[/tex]
[tex]\frac{116}{159} = 0.7296[/tex] probability that a randomly chosen applicant has over 10 years of experience, given that the applicant has a graduate degree.
