Rui is a professional deep water free diver. His altitude (in meters relative to sea level), xxx seconds after diving, is modeled by: d(x)=\dfrac12x^2 -10xd(x)= 2 1 ​ x 2 −10xd, left parenthesis, x, right parenthesis, equals, start fraction, 1, divided by, 2, end fraction, x, squared, minus, 10, x How many seconds after diving will Rui reach his lowest altitude?

Respuesta :

Answer:

Rui will reach his lowest altitude after 20seconds of diving

Step-by-step explanation:

Given the function that models the altitude of Rui at any time x expressed as:

d(x) = 1/2 x² - 10x

The height of rui at his lowest altitude will be zero. Substitute d(x) = 0 into the expression and get x

d(x) = 1/2 x² - 10x

0 = 1/2 x² - 10x

-1/2x² = 10x

1/2 x = 10

Multiply both sides by 2

x/2 × 2 = 10×2

x×1 =20

x = 20

Hence Rui will reach his lowest altitude after 20seconds of diving

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