Answer:
2(x-10)/(x+10)(x-4)
Step-by-step explanation:
Find the complete question attached as a diagram
Given the following
F(x) = x-16/x²+6x-40
Factoring the denominator
F(x) = x-16/x²-4x+10x-40.
F(x) = x-16/x(x-4)+10(x-4)
F(x) = x-16/(x+10)(x-4)
g(x) = 1/x+10
Adding both functions
F(x)+g(x) = x-16/(x+10)(x-4) + 1/x+10.
F(x)+g(x) = x-16+(x-4)/(x+10)(x-4)
F(x)+g(x) = x-16+x-4/(x+10)(x-4)
F(x)+g(x) = x+x-16-4/(x+10)(x-4)
F(x)+g(x) = 2x-20/(x+10)(x-4)
F(x)+g(x) = 2(x-10)/(x+10)(x-4)
