Answer:
In 4 Easter egg hunts she found 14 eggs
Step-by-step explanation:
The table is missing, but the thing we need to complete in the table is a number X, where X is the number of easter egg hunts where she found 14 eggs.
We already know that:
2 times she found 8 eggs
4 times she found 11 eggs
X times she found 14 eggs.
And we also know that the average is 11.6 eggs.
Where the average can be computed as:
The quotient between all the eggs she found in all the Easter egg hunts, and the total number of Easter egg hunts were she attended.
She got a total of: 2*8 eggs + 4*11 eggs + X*14 eggs.
And she attended a total of 2 + 4 + X Easter egg hunts, then:
This is then:
[tex]avg = \frac{2*8 + 4*11 + X*14}{2 + 4 + X} = 11.6[/tex]
Now we just need to solve the above equation for X.
We can rewrite this as:
[tex]2*8 + 4*11 + X*14 = 11.6*(2 + 4 + X)[/tex]
[tex]16 + 44 + X*14 = 11.6*(6 + X)[/tex]
[tex]60 + X*14 = 11.6*(6 + X) = 11.6*X + 69.6[/tex]
[tex](14 - 11.6)*X = 69.6 - 60[/tex]
[tex]2.4*X = 9.6[/tex]
X = 9.6/2.4 = 4
This means that in 4 Easter egg hunts she found 14 eggs.
