Removing the denominator by dividing both the numerator's terms by 2 is the needed next step for simplification. The result is: x=−2±2√6
How to find the solution to a standard quadratic equation?
Suppose the given quadratic equation is
[tex]ax^2 + bx + c = 0[/tex]
Then its solutions are given as
[tex]x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}[/tex]
Here, we're given the expression:
[tex]x = \dfrac{-4 \pm 4\sqrt{6}}{2}[/tex]
The next step to simplify is to make it look more simple.
[tex]x = \dfrac{-4}{2} \pm \dfrac{4\sqrt{6}}{2}\\\\x = -2 \pm 2\sqrt{6}[/tex]
Thus, removing the denominator by dividing both the numerator's terms by 2 is the needed next step for simplification. The result is: x=−2±2√6
Learn more about quadratic equations here:
https://brainly.com/question/3358603
