Answer:
[tex]n=4.5\times 10^{13}[/tex]
Explanation:
Initial charge, [tex]q_1=10\mu C[/tex]
After conduction, charge on the body becomes, Â [tex]q_2=-2.8\mu C[/tex]
We need to find the number of electrons gained by this charged body.
Net charge,
[tex]q=q_1+q_2\\\\=10+(-2.8)\\\\=7.2\ \mu C[/tex]
Let n be the number of electrons gained by this charged body. So,
[tex]q=ne\\\\n=\dfrac{q}{e}\\\\n=\dfrac{7.2\times 10^{-6}}{1.6\times 10^{-19}}\\\\=4.5\times 10^{13}[/tex]
So, [tex]4.5\times 10^{13}[/tex] electrons gained by this charged body.
