Answer:
The test statistic needed to evaluate the claim is t = -1.08.
Step-by-step explanation:
The test statistic is:
[tex]t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}[/tex]
In which X is the sample mean, [tex]\mu[/tex] is the expected value of the mean, s is the standard deviation of the sample and n is the size of the sample.
At a certain university, the average attendance at basketball games has been 3125. The athletic director claims that the attendance is the same as last year.
This means that [tex]\mu = 3125[/tex]
Due to the dismal showing of the team this year, the attendance for the first 9 games has averaged only 2915 with a standard deviation of 585.
This means that [tex]n = 9, X = 2915, s = 585[/tex]
What is the test statistic needed to evaluate the claim?
[tex]t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}[/tex]
[tex]t = \frac{2915 - 3125}{\frac{585}{\sqrt{9}}}[/tex]
[tex]t = -1.08[/tex]
The test statistic needed to evaluate the claim is t = -1.08.
