[tex]\huge{\mathbb{\tt { PROBLEM:}}}[/tex]
if h(x)=3^x then h (-4) =
[tex]\huge{\mathbb{\tt { ANSWER:}}}[/tex]
[tex] \frac{1}{81} [/tex]
[tex]\huge{\mathbb{\tt { EXPLANATION:}}}[/tex]
In h(x) = 3^x , you must replace each instance of with -4:
h(-4)=3^(-4)
[tex]h(4)= \frac{1}{3^4} = \frac{1}{81} [/tex]
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