Answer:
x²+8x+9=0
Comparing above equation with ax²+bx +c
we get
a=1
b=8
c=9
quadratic equation is
[tex]x = \frac{ - 8± \sqrt{ {8}^{2} - 4×1×9} }{2*1} [/tex]
[tex]x = \frac{ -8± \sqrt{ 64-36} }{2} [/tex]
2x+8=±[tex] \sqrt{ {28}}[/tex]
taking + ve
2x=[tex] \sqrt{ {28}}[/tex]-8
x=[tex] 2\sqrt{ {7}}[/tex]-8/2
x=[tex] \sqrt{ {7}}[/tex]-4
taking -ve
2x=-[tex] \sqrt{ {28}}[/tex]-8
x=-[tex] 2\sqrt{ {7}}[/tex]-8/2
x=-[tex] \sqrt{ {7}}[/tex]-4
