Answer: D. -7x-5y=-48
Step-by-step explanation:
The slope of AB is [tex]\frac{-1-4}{-3-4}=\frac{5}{7}[/tex]. Since perpendicular lines have slopes that are negative reciprocals, the slope of BC is -7/5.
Substituting into point-slope form,
[tex]y-4=-\frac{7}{5}(x-4)\\\\5y-20=-7(x-4)\\\\5y-20=-7x+28\\\\\boxed{-7x-5y=-48}[/tex]
