The correct equilibrium constant expression for this equation C6H1206(s) + 60,(g) <—>6C02(g)+ 6H2O(g) will be
keq = 6[co2] 6[h2o] / [c6h1206] 6[o].
All reactions tend towards the state of chemical equilibrium. It is the point at which both the forward process and the reverse process are taking place at the same rate.
Since the forward and reverse rates are equal, hence the concentrations of the reactants and products will be constant at the equilibrium state. Here, it is important to remember that even though the concentrations are constant at equilibrium.
The double half-arrow sign we use for writing the reversible reaction equations. It is represented as ⇌ a sign of equilibrium.
therefore, the correct equilibrium constant expression will be C6H1206(s) + 60,(g) <—>6C02(g)+ 6H2O(g)
Learn more about the equilibrium constant, here:
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