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What is the line of symmetry for the parabola whose equation is y = x2 + 10x + 25?

A-x = -5
B-x = 5
C-x = -10

Respuesta :

altavistard

Answer:

x = -5

Step-by-step explanation:

Please write this as y = x^2 + 10x + 25.  Here the coefficients are {1, 10, 25}.

The equation of the axis of symmetry is x = -b/[2a], which here is

x = -10 / [2*1] = -5

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