EFGH is a parallelogram. Find the measure of JG.

[tex] \large{ { \tt{꧁ \: A\: N \: S \: W \: E \: R \: ꧂}}}: [/tex]
Step-by-step explanation:
✧ [tex] \underline{ \underline{ \large{ \red{\tt{ \: P \: R \: O \: V \: I\: D \: E \: D\: }} }}: }[/tex]
✎ [tex] \underline{ \underline{ \purple{ \large\tt{T\: O \: \: F \: I\: N \: D}}}} : [/tex]
Since we know , The diagonals of a parallelogram bisect each other ;
[tex] \large{\text{EF \: = JG}}[/tex]
➝ [tex] \large{ \bf{3w = w + 8}}[/tex]
➝ [tex] \large{ \bf{3w - w = 8}}[/tex]
➝ [tex] \large{ \bf{2w = 8}}[/tex]
➝ [tex] \large{ \bf{w = \frac{8}{2}}} [/tex]
➝ [tex] \boxed{\large{ \bf{w = 4}}}[/tex]
♔ [tex] \underline{ \text{Replacing \: Value}} : [/tex]
⇢[tex] \large{ \bf{JG = w + 8 = 4 + 8 = \boxed{ \bf{12}}}}[/tex]
Yayy! We found our answer ☾
⛧ [tex] \boxed{ \boxed{ \orange{\tt{Our \: Final \: Answer : \underline{ \boxed{ \tt{12}}}}}}}[/tex]
Hope I helped! ♡
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⋆ [tex] \underbrace{ \overbrace{ \mathfrak{Carry \:On \: Learning}}}[/tex] ⋆
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