Answer:
B. Attract each other with a force of 10 newtons.
Explanation:
Statement is incorrectly written. The correct form is: A [tex]+10\,\mu C[/tex] charge and a [tex]-10\,\mu C[/tex] at a distance of 0.3 meters.
The two particles have charges opposite to each other, so they attract each other due to electrostatic force, described by Coulomb's Law, whose formula is described below:
[tex]F = \frac{\kappa \cdot |q_{A}|\cdot |q_{B}|}{r^{2}}[/tex] (1)
Where:
[tex]F[/tex] - Electrostatic force, in newtons.
[tex]\kappa[/tex] - Electrostatic constant, in newton-square meters per square coulomb.
[tex]|q_{A}|,|q_{B}|[/tex] - Magnitudes of electric charges, in coulombs.
[tex]r[/tex] - Distance between charges, in meters.
If we know that [tex]\kappa = 8.988\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}}[/tex], [tex]|q_{A}| = |q_{B}| = 10\times 10^{-6}\,C[/tex] and [tex]r = 0.3\,m[/tex], then the magnitude of the electrostatic force is:
[tex]F = \frac{\kappa \cdot |q_{A}|\cdot |q_{B}|}{r^{2}}[/tex]
[tex]F = 9.987\,N[/tex]
In consequence, correct answer is B.
