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Fig. 2.1 shows a hammer being used to drive a nail into a piece of wood.
hammer head
-nail
wood
Fig. 2.1
The mass of the hammer head is 0.15 kg.
The speed of the hammer head when it hits the nail is 8.0m/s.
The time for which the hammer head is in contact with the nail is 0.0015s.
The hammer head stops after hitting the nail.
(a) Calculate the change in momentum of the hammer head.

Respuesta :

hamzaahmeds

Answer:

ΔP = - 1.2 Ns

Explanation:

The change in momentum of the hammer head can be given as follows:

[tex]\Delta P = P_f - P_i\\[/tex]

where,

ΔP = Change in Momentum = ?

Pf = Final Momentum

Pi - Initial Momentum

Therefore,

[tex]\Delta P = mv_f - mv_i\\\Delta P = m(v_f - v_i)[/tex]

where,

m = mass of hammer head = 0.15 kg

vf = final speed of hammer = 0 m/s

vi = initial speed of hammer = 8 m/s

Therefore,

[tex]\Delta P = (0.15\ kg)(0\ m/s-8\ m/s)[/tex]

ΔP = - 1.2 Ns

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