Answer:
v = 2.91 m/s
Explanation:
Given that,
A kayaker is paddling south at 2.50 m/s, and encounters a weird current moving 1.15 m/s west.
We need to find the resultant velocity. Both velocities are perpendicular to each other. So,
[tex]v=\sqrt{v_1^2+v_2^2} \\\\=\sqrt{2.5^2+1.5^2} \\\\=2.91\ m/s[/tex]
So, the magnitude of the resultant velocity is equal to 2.91 m/s.
