Answer:
D [tex] (x +6) ^2 +(y-1)^2 =7 [/tex]
Step-by-step explanation:
Center of the circle (h, k) = (-6, 1)
Area of the circle [tex] =\pi r^2 [/tex]
[tex] 7\pi=\pi r^2 [/tex]
[tex] \frac {7\pi}{\pi} =r^2 [/tex]
[tex]r^2=7[/tex]
[tex]r=\sqrt 7[/tex]
Radius [tex] r=\sqrt {7}[/tex]
Equation of circle in center radius form is given as:
[tex] (x - h) ^2 +(y-k) ^2 =r^2 [/tex]
Plugging the values of h, k and r in the above equation, we find:
[tex] [x - (- 6)] ^2 +[y-1 ]^2 =(\sqrt {7})^2 [/tex]
[tex] (x +6) ^2 +(y-1)^2 =7 [/tex]
