Answer:
[tex]\boxed {\boxed {\sf 9.6 \ mol \ KCl}}[/tex]
Explanation:
We must use stoichiometry to solve this, which is the calculation of reactants and products in a reaction using ratios.
Let's analyze the reaction given.
[tex]MgCl_2 _{(aq)} + K_2SO_4 _{(aq)} \rightarrow 2KCl _{(aq)} + MgSO_4 _{(s)}[/tex]
Now, look at the coefficients, or numbers in front of the molecule formulas. If there isn't a coefficient, then a 1 is implied.
We want to find how many moles of potassium chloride (KCl) are produced from 4.8 moles of magnesium chloride (MgCl₂). Check the coefficients for these molecules.
The coefficient represents the number of moles. Therefore, 1 mole of magnesium chloride produces 2 moles of potassium chloride. We can set up a ratio using this information.
[tex]\frac { 1 \ mol \ MgCl_2} {2 \ mol \ KCl}[/tex]
Multiply by the given number of moles of magnesium chloride: 4.8
[tex]4.8 \ mol \ MgCl_2 *\frac { 1 \ mol \ MgCl_2} {2 \ mol \ KCl}[/tex]
Flip the ratio so the moles of magnesium chloride cancel out.
[tex]4.8 \ mol \ MgCl_2 *\frac {2 \ mol \ KCl} { 1 \ mol \ MgCl_2}[/tex]
[tex]4.8 *\frac {2 \ mol \ KCl} { 1 \ } }[/tex]
[tex]4.8 * {2 \ mol \ KCl}[/tex]
[tex]9.6 \ mol \ KCl[/tex]
9.6 moles of potassium chloride are produced from 4.8 moles of magnesium chloride.
