Answer:
See Explanation
Step-by-step explanation:
The question has missing details, as the scale factor is not given. However, I will give a general explanation on how to calculate the area and perimeter of a dilated shape (triangle).
The following assumptions, apply:
(1) Scale factor of 1/2 from the blue to the yellow triangle.
(2) The dimension of the blue triangle are:
[tex]Base = x[/tex]
[tex]Sides= y\ and\ z[/tex]
[tex]Height= h[/tex]
First, calculate the dimensions of the yellow triangle.
The dimension will be the product of the scale factor and the dimensions of the blue triangle.
So, we have:
[tex]Base = \frac{1}{2} * x = \frac{1}{2}x[/tex]
[tex]Sides = \frac{1}{2}y\ and\ \frac{1}{2}z[/tex]
[tex]Height = \frac{1}{2}h[/tex]
The perimeter of the blue triangle is:
[tex]P_1 =Base + Sides[/tex]
[tex]P_1 = x + y + z[/tex]
The perimeter of the yellow triangle is:
[tex]P_2 =Base + Sides[/tex]
[tex]P_2 = \frac{1}{2}x + \frac{1}{2}y + \frac{1}{2}z[/tex]
Factorize
[tex]P_2 = \frac{1}{2}[x + y + z][/tex]
Recall that: [tex]P_1 = x + y + z[/tex]
So:
[tex]P_2 = \frac{1}{2}*P_1[/tex]
This implies that the perimeter of the yellow triangle is a product of the scale factor and the perimeter of the blue triangle.
The area of the blue triangle is:
[tex]A_1 = \frac{1}{2}* Base * Height[/tex]
[tex]A_1 = \frac{1}{2} * x* h[/tex]
[tex]A_1 = \frac{1}{2} xh[/tex]
The area of the yellow triangle is:
[tex]A_2 = \frac{1}{2} * Base * Height[/tex]
[tex]A_2 = \frac{1}{2}* (\frac{1}{2}x) * (\frac{1}{2}h)[/tex]
Rewrite as:
[tex]A_2 = \frac{1}{2}* \frac{1}{2} [\frac{1}{2}x h][/tex]
[tex]A_2 = (\frac{1}{2})^2 *[\frac{1}{2}x h][/tex]
Recall that:[tex]A_1 = \frac{1}{2} xh[/tex]
So:
[tex]A_2 = (\frac{1}{2})^2 *A_1[/tex]
This implies that the area of the yellow triangle is a product of the square of the scale factor and the area of the blue triangle.
