Answer:
Let E denote the event of choosing a jury with 10 men and 2 women.
The sample space for selecting 12 members from the pool contains 55C12 elements.
The number of ways of selecting 10 men and 2 women is 26C10 29C2.
The probability of event E =
The probability of selecting a jury with 10 men and 2 women is 0.005 (0.5%).
Step-by-step explanation:
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Answer:
The probability of selecting a jury with 10 men and 2 women out of out of 29 men and 26 women is 0.005 (0.5%)
Step-by-step explanation:
Let P(E) denote the probability of choosing a jury with 10 men and 2 women out of 29 men and 26 women.
The sample space for selecting 12 members from the total no of member will be 55c12
The number of ways of selecting 10 men and 2 women is 26c10 29c2.
The probability of event E = [tex]$=P(E)=\frac{{ }_{20} C_{10} \times{ }_{20} C_{2}}{-C_{12}}$[/tex]
[tex]$=\frac{5,311,735 \times 406}{438,729,741,450}$[/tex] [tex]$=0.005$.[/tex]
The probability of selecting a jury with 10 men and 2 women is 0.005 (0.5%).
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