Which function would be produced by a horizontal stretch of the graph of y = sqrt(x) followed by a reflection in the x - axis ?

Answer:
the answer is the first one
Step-by-step explanation:
Explanation: be im smart
Function transformation involves changing the form of a function
A function that could represent the transformed function is function (c) [tex]f(x) = -\sqrt{\frac 12 x}[/tex]
The equation of the function is given as:
[tex]f(x) = \sqrt x[/tex]
The rule of horizontal stretch is:
[tex](x,y) \to (ax,y)[/tex]
Where:
[tex]0 < a < 1[/tex]
Take for instance:
[tex]a = \frac 12[/tex]
So, we have:
[tex]f(x) = \sqrt{\frac 12 x}[/tex]
Next, the function is reflected in across the x-axis.
The rule of this transformation is:
[tex](x,y) \to (x,-y)[/tex]
So, we have:
[tex]f(x) = -\sqrt{\frac 12 x}[/tex]
Hence, a function that could represent the transformed function is function (c)
Read more about function transformation at:
https://brainly.com/question/1548871