a click beetle abruptly releases elastic energy stored in its body to launch itself into the air. the function h(t)=-16t^2+12t represents the height h (in feet) of the click beetle t seconds after launching. the height of a second click beetle t seconds after launching is shown in the graph. which click beetle went higher?

a click beetle abruptly releases elastic energy stored in its body to launch itself into the air the function ht16t212t represents the height h in feet of the c class=

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Answer:

The first click beetle reaches a maximum height of 2.25 feet. From the graph, you can see that the second click beetle reaches a maxium height of between 1.5 and 1.6 feet. So, the first click beetle went higher.

A beetle reaches a maximum height of 2.25 meters after 2,25 seconds

How to determine the maximum height?

The function is given as:

h(t)=-16t^2+12t

Differentiate

h'(t)= -32t + 12

Set to 0

-32t + 12 = 0

Add 32t to both sides

32t = 12

Divide both sides by 32

t = 0.375

Substitute t = 0.375 in h(t)

h(0.375) = -16 * 0.375^2 + 12 * 0.375

Evaluate

h(0.375) = 2.25

The above means that a beetle reaches a maximum height of 2.25 meters after 2,25 seconds

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