A grain dealer sold to one customer 5 bushels of wheat, 2 of com, and 3 of ryo, for $228: to another, 2 of wheat, 3 of corn, and 5 of ryo, for $228, and to a third, 3 of wheat, 5 of com, and 2 of rye, for $228. What was the price per bushel for com?

Respuesta :

101028

Answer:

2.30 :) hope this helps!!!!!!! :)

Step-by-step explanation:

w = wheat     c = corn    r = rye

6w + 3c + 6r = 45.90

3w + 6c + 6r = 49.20

6w + 6c + 3r = 41.40

since you want the answer for c, manipulate then add 2 equations that will get rid of 1 variable:

if we multiply the first equation by -1 then add it to the second equation, it will eliminate the r

-6w -  3c -  6r = - 45.90

3w + 6c + 6r =   49.20

------------------------------------

- 3w +3c  =      3.30    or     w - c = - 1.10

If we multiply the 3rd equation by -2 then add it to the first equation, it will eliminate the  r  again:

-12w - 12c -  6r = - 82.80

  6w + 3c + 6r =    45.90

------------------------------------------

- 6w - 9c         =  - 36.90   or       2w + 3c  =   12.30

now we have 2 equations and 2 variables that we can solve by substitution:

w = c - 1.10

2(c - 1.10)  + 3c = 12.30

2c - 2.20 + 3c   =   12.30

5c = 14.50

c = 2.90      

w = c - 1.10   or  1.80

3r = 41.40 - 6(1.80) - 6(2.90)

3r = 13.20    r = 4.40

I will pick the 2nd equation to check my answers :)!

3(1.80) +  6(2.90)  + 6(4.40)  = 49.20

5.40 + 17.40 + 26.40 =  49.20

As per linear equation, the price per bushel for corn is $22.8.

What is a linear equation?

A linear equation is an equation that has one or multiple variable with the highest power of the variable is 1.

Given, a grain dealer sold to one customer 5 bushels of wheat, 2 of corn, and 3 of rye, for $228.

To another customer, he sold 2 of wheat, 3 of corn, and 5 of rye, for $228.

To a third customer, 3 of wheat, 5 of corn, and 2 of rye, for $228.

Let, per piece of wheat is of $x.

Per piece of corn is of $y.

Per piece of rye is of $z.

Therefore, 5x + 2y + 3z = 228 ....(1)

2x + 3y + 5z = 228 .........................(2)

3x + 5y +2z = 228 ..........................(3)

Multiplying equation(1) by '2' and equation(2) by '5' and substract, we get:

2(5x + 2y + 3z) - 5(2x + 3y + 5z) = 2(228) - 5(228)

⇒ (10x + 4y + 6z) - (10x + 15y + 25z) = - 3(228)

⇒ (- 11y - 19z) = - 684

⇒ 11y + 19z = 684 ......(4)

Multiplying equation(2) by '3' and equation(3) by '2' and substract, we get:

3(2x + 3y + 5z) - 2(3x + 5y +2z) = 3(228) - 2(228)

⇒ (6x + 9y + 15z) - (6x + 10y + 4z) = 228

⇒ - y + 11z = 228 .......(5)

Now, multiplying equation(5) by '11' and then add with equation (4), we get:

 11y + 19z + 11(- y + 11z) = 684 + 11(228)

⇒ 140z = 3192

⇒ z = 22.8

Putting the value of 'z' in equation (5) we get:

- y + 11(22.8) = 228

⇒ y = 22.8

Now, putting the values of 'y' and 'z' in equation (1), we get:

5x + 2(22.8) + 3(22.8) = 228

⇒ 5x = 114

⇒ x = 22.8

Learn more about linear equation here: https://brainly.com/question/22990272

#SPJ3

ACCESS MORE
ACCESS MORE
ACCESS MORE
ACCESS MORE