The figure shows a 1300​-yard-long sand beach and an oil platform in the ocean. The angle made with the platform from one end of the beach is 84 degrees and from the other end is 76 degrees . Find the distance of the oil​ platform, to the nearest tenth of a​ yard, from each end of the beach.

Respuesta :

Answer:

y = 3,254.3 yd

Step-by-step explanation:

Lets denote with 'x' and 'y' the distances we need to find.

Using the Law of Sines we can write:

x/(sin 76) = 1175/(sin(180 - (83 + 76))

x/(sin 76) = 1175/(sin 21)

x = 3,181.4 yd

y/(sin 83) = 1175/(sin(180 - (83 + 76))

y/(sin 83) = 1175/(sin 21)

y = 3,254.3 yd

The platform is 3,181.4 yards far from one end of the beach and 3,254.3 yd far from the other.

The distance of the oilplatform is 3708.82 yards, from each end of the beach.

Given that,

The figure shows a 1300​-yard-long sand beach and an oil platform in the ocean.

The angle made with the platform from one end of the beach is 84 degrees and from the other end is 76 degrees.

We have to determine,

The distance of the oilplatform, to the nearest tenth of a​ yard, from each end of the beach.

According to the question,

Let x be the distance of the sand beach,

And y be the distance of oil platform.

The distance of the oilplatform of a​ yard, from each end of the beach, is determined by using the sin rule,

[tex]\rm \dfrac{x}{sina} = \dfrac{y}{sinb}\\\\ \dfrac{x}{sin76} = \dfrac{1300}{sin(180-(84+76))}\\\\ \dfrac{x}{0.97} = \dfrac{1300}{sin(180-160)}\\\\\dfrac{x}{0.97} = \dfrac{1300}{sin20}\\\\\dfrac{x}{0.97} = \dfrac{1300}{0.34}\\\\ \dfrac{x}{0.97}= 3823.52 \\\\ x = 3823.52 \times 0.97\\\\x = 3708.82[/tex]

Hence, The distance of the oilplatform is 3708.82 yards, from each end of the beach.

For more details refer to the link given below.

https://brainly.com/question/18188038

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