Respuesta :
Answer: [tex]6.38\times 10^{23}[/tex] molecules of water are produced.
Explanation:
To calculate the moles :
[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]
[tex]\text{Moles of} Fe(OH)_3=\frac{75.50g}{106.8g/mol}=0.707moles[/tex]
The balanced chemical reaction is:
[tex]2Fe(OH)_3\rightarrow Fe_2O_3+3H_2O[/tex]
According to stoichiometry :
2 moles of [tex]Fe_2O_3[/tex] produce = 3 moles of [tex]H_2O[/tex]
Thus 0.707 moles of [tex]Fe_2O_3[/tex] will produce=[tex]\frac{3}{2}\times 0.707=1.06moles[/tex] of [tex]H_2O[/tex]
According to avogadro's law, 1 mole of every substance contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
Thus 1.06 moles of [tex]H_2O[/tex] contains = [tex]\frac{6.023\times 10^{23}}{1}\times 1.06=6.38\times 10^{23}[/tex] molecules
