Answer:
x = 15
z = 25
Step-by-step explanation:
In [tex] \odot\: O, \: \angle MLK [/tex] is inscribed in a semicircle.
[tex] \therefore m\angle MLK =90\degree [/tex]
[tex] \therefore 6x\degree =90\degree [/tex]
[tex] \therefore 6x =90[/tex]
[tex] \therefore x =\frac{90}{6}[/tex]
[tex] \therefore x =15[/tex]
In [tex] \odot\: A, \: \angle PRQ[/tex] is inscribed in a semicircle.
[tex] \therefore m\angle PRQ =90\degree [/tex]
[tex] \therefore (4z-10)\degree =90\degree [/tex]
[tex] \therefore 4z-10 =90[/tex]
[tex] \therefore 4z =100[/tex]
[tex] \therefore z =\frac{100}{4}[/tex]
[tex] \therefore z =25[/tex]
