Answer: 56.2 g of Aluminium is needed to react fully with 100 grams of sulphur.
Explanation:
To calculate the moles :
[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]
[tex]\text{Moles of} S=\frac{100g}{32g/mol}=3.125moles[/tex]
The balanced chemical equation is:
[tex]2Al+3S\rightarrow Al_2S_3[/tex]
According to stoichiometry :
3 moles of [tex]S[/tex] require = 2 moles of [tex]Al[/tex]
Thus 3.125 moles of [tex]S[/tex] will require=[tex]\frac{2}{3}\times 3.125=2.08moles[/tex] of [tex]Al[/tex]
Mass of [tex]Al=moles\times {\text {Molar mass}}=2.08moles\times 27g/mol=56.2g[/tex]
Thus 56.2 g of Aluminium is needed to react fully with 100 grams of sulphur.
