Answer:
[tex]36.44\ \text{kg m/s}\hat{i}[/tex]
Explanation:
I = Moment of inertia of sphere = [tex]\dfrac{2}{5}MR^2[/tex]
M = Mass of sphere = 29 kg
R = Radius of sphere = 0.5 m
T = Time taken for one revolution = 0.5 s
[tex]\omega[/tex] = Angular velocity = [tex]\dfrac{2\pi}{T}[/tex]
[tex]L=I\omega\\\Rightarrow L=\dfrac{2}{5}MR^2\dfrac{2\pi}{T}\\\Rightarrow L=\dfrac{4MR^2\pi}{5T}\\\Rightarrow L=\dfrac{4\times 29\times 0.5^2\pi}{5\times 0.5}\\\Rightarrow L=36.44\ \text{kg m/s}[/tex]
The rotational angular momentum of the sphere is [tex]36.44\ \text{kg m/s}\hat{i}[/tex].
