Solution :
The balanced chemical equation are
The Catabolism of the glucose takes place in five stages :
1. Glucose + [tex]$ATP$[/tex] → glucose - [tex]$6$[/tex] - phosphate [tex]$+ ADP$[/tex] , [tex]$\Delta G^0=-16.7 \ kJ/mol$[/tex]
2. Glucose - [tex]$6$[/tex] - phosphate → Fructose - [tex]$6$[/tex] - phosphate , [tex]$\Delta G^0=1.7 \ kJ/mol$[/tex]
3. Glucose - [tex]$6$[/tex] - phosphate + [tex]$ATP$[/tex] → [tex]$ADP$[/tex] + Fructose - [tex]$1,6- \text{biophosphate}$[/tex], [tex]$\Delta G^0=-14.2 \ kJ/mol$[/tex]
4. Fructose - [tex]$1,6- \text{biophosphate}$[/tex] → dihydroxyacetonephosphate + glyceraldehyde [tex]$-3 - $[/tex] phosphate, [tex]$\Delta G^0=23.8 \ kJ/mol$[/tex]
5. Dihydroxyacetonephosphate → glyceraldehyde [tex]$-3 - $[/tex] phosphate , [tex]$\Delta G^0=7.5 \ kJ/mol$[/tex]
Therefore, the overall net equations
Glucose + [tex]$2ATP \rightarrow$[/tex] glyceraldehyde [tex]$-3 - $[/tex] phosphate + [tex]$2ADP$[/tex] [tex]$\Delta G^0=2.1 \ kJ/mol$[/tex]
