Answer:
[tex]N_a=1.8*10^{-6}kg/sm^2[/tex]
Explanation:
From the question we are told that:
Thickness of plastic membrane [tex]L_t=0.3mm[/tex]
The temperature of hydrogen [tex]T_h=25 \textdegree C[/tex]
Diffusion coefficient of hydrogen in the plastic [tex]25 \textdegree C \mu=9*10-8m2/s[/tex]
The solubility of hydrogen in the plastic membrane [tex]\+x=1.5*10{-3} kmol/m3[/tex]
Generally the equation for molar conc is mathematically given by
[tex]CA_1=x*bar[/tex]
3bars
[tex]CA_1=1.5*10^{-3}*3[/tex]
[tex]CA_1=4.5*10^{-3}kmol/m^3[/tex]
1bar
[tex]CA_1=1.5*10^{-3}*1[/tex]
[tex]CA_1=1.5*10^{-3}kmol/m^3[/tex]
Generally the equation for molar diffusion flux of Hydrogen N_a is mathematically given by
[tex]N_a=\frac{D{AB}}{\L}(CA_1-CA_2)[/tex]
[tex]N_a=\frac{9*10^{-8}}{0.3*10^-^3} (4.5*10^{-3}-1.5*10^{-3})kmoi/m^-3[/tex]
[tex]N_a=9.*10^{-7}kmol/sm^2*2kh/kmole[/tex]
[tex]N_a=1.8*10^{-6}kg/sm^2[/tex]
