A string with a length of 0.75 m is fixed at both ends. (a) What is the longest possible wavelength for the traveling waves that can interfere to form a standing wave on this string? (b) If waves travel with a speed of 130 m/s on this string, what is the frequency associated with this longest wavelength?

Respuesta :

Answer:

a) Longest wavelength is: [tex]\lambda_{1}=2*0.75=1.5\: m[/tex]

b) The frequency associated with this longest wavelength is: [tex]f=86.7\: Hz[/tex]

Explanation:

a)

The wavelength equation of a standing wave is given by:

[tex]\lambda_{n}=\frac{2}{n}L[/tex]

Where:

  • L is the length of the string
  • n is a natural number

We use n=1 to find the longest possible wavelength, so we will have:

[tex]\lambda_{1}=2L[/tex]

[tex]\lambda_{1}=2*0.75=1.5\: m[/tex]

b)

The speed of the wave is given by:

[tex]v=f\lambda[/tex]

So we just need to find the f (frequency).

[tex]f=\frac{v}{\lambda}[/tex]

[tex]f=\frac{130}{1.5}[/tex]

[tex]f=86.7\: Hz[/tex]

I hope it helps you!

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