Be sure to answer all parts. For an aqueous solution of sodium chloride (NaCl), determine the molarity of 4.05 L of a solution that contains 195 g of sodium chloride. M Determine the volume of this solution that would contain 4.63 moles of sodium chloride. L Determine the number of moles of sodium chloride in 25.35 L of this solution. mol

Respuesta :

Answer:

[tex]0.824\ \text{M}[/tex]

[tex]5.62\ \text{L}[/tex]

[tex]20.89\ \text{mol}[/tex]

Explanation:

Molar mass of NaCl = 58.44 g/mol

Mass of NaCl = 195 g

Volume of solution = 4.05 L

Molarity of solution is

[tex]\dfrac{195}{4.05}\times \dfrac{1}{58.44}=0.824\ \text{M}[/tex]

The molarity of the solution is [tex]0.824\ \text{M}[/tex]

Moles of NaCl = 4.63 mol

Volume is given by

[tex]\dfrac{4.63}{0.824}=5.62\ \text{L}[/tex]

The volume of the solution that contains the required amount NaCl is [tex]5.62\ \text{L}[/tex]

Volume of solution = [tex]25.35\ \text{L}[/tex]

Moles of solution is given by

[tex]0.824\times 25.35=20.89\ \text{mol}[/tex]

The number of moles of NaCl is [tex]20.89\ \text{mol}[/tex].

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