Respuesta :

Answer:

B. 0.05

Explanation:

The reaction that takes place is:

  • HCl + NaOH → NaCl + H₂O

As 1 mol of NaOH reacts with 1 mol of HCl, to solve this problem what we need to do is calculate the number of NaOH moles contained in 0.1 liters of a 0.5 M solution:

  • Molarity = Moles / liters
  • Moles = Molarity * liters
  • 0.5 M * 0.1 L = 0.05 mol

The moles of Hydrogen chloride required to neutralize the 0.1 liter of 0.5 M Sodium hydroxide is 0.05 moles.

How do we calculate moles?

Moles (n) of any substance will be calculated by using the molarity (M) as:

M = n/V, where

V = volume

Given chemical reaction is:
NaOH +HCl → NaCl + H₂O

Moles of 0.5M NaOH will be calculated as:
n = (0.5)(0.1) = 0.05 moles

From the stoichiometry of the reaction it is clear that:

1 mole of NaOH = react with 1 mole of HCl

0.05 mole of NaOH = react with 0.05 mole of HCl

Hence option (B) is correct.

To know more about moles, visit the below link:

https://brainly.com/question/15374113

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