Respuesta :
Answer:
The answer is "no".
Step-by-step explanation:
No, because the probability besides simultaneous flights to arrive on time are not self-sufficient for every flight (when the first flight was late, therefore the probabilities during the next flight were significantly greater), because then the standard multiplication principle would be used for explanatory variables.
Yes, we can multiply (0.85)(0.85)(0.85)(0.85)
Let the four flight be represented by A, B, C, and D respectively
Probability that each of the flights arrive on time is 0.85
That is:
Probability that flight A arrives on time, P(A) = 0.85
Probability that flight B arrives on time, P(B) = 0.85
Probability that flight C arrives on time, P(C) = 0.85
Probability that flight D arrives on time, P(D) = 0.85
Probability that the next four flights arrive on time will be:
P(A) x P(B) x P(C) x P(D) = 0.85 x 0.85 x 0.85 x 0.85
Yes, we can multiply (0.85)(0.85)(0.85)(0.85)
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