NEED ANSWERS NOW!! (Reward) brainlest and pointsss

Answer:
B
Step-by-step explanation
f(x)=x2-4x-5
Becomes
f(x)=x2-5x+x-5
Take out the common factor
f(x)=(x-5)(x+1)
Equate the given function equal to 0
0=(x-5)(x+1)
And then
x-5=0 -- x=5
x+1 = 0 == x=-1
Answer:
B
Step-by-step explanation:
we are given a quadratic function
we want to figure out the form which we don't need change
so according to the question
[tex] \displaystyle{x}^{2} - 4x - 5 = 0[/tex]
rewrite -4x as x-5x:
[tex] \displaystyle{x}^{2} + x - 5x- 5 = 0[/tex]
factor out x:
[tex] \displaystyle \: x({x}^{} + 1)- 5x- 5 = 0[/tex]
factor out -5:
[tex] \displaystyle \: x({x}^{} + 1)- 5(x + 1 )= 0[/tex]
group:
[tex] \displaystyle \: (x + 1 )(x - 5)= 0[/tex]
hence our answer is B