Respuesta :

Answer:

B

Step-by-step explanation

f(x)=x2-4x-5

Becomes

f(x)=x2-5x+x-5

Take out the common factor

f(x)=(x-5)(x+1)

Equate the given function equal to 0

0=(x-5)(x+1)

And then

x-5=0 -- x=5

x+1 = 0 == x=-1

Nayefx

Answer:

B

Step-by-step explanation:

we are given a quadratic function

we want to figure out the form which we don't need change

so according to the question

[tex] \displaystyle{x}^{2} - 4x - 5 = 0[/tex]

rewrite -4x as x-5x:

[tex] \displaystyle{x}^{2} + x - 5x- 5 = 0[/tex]

factor out x:

[tex] \displaystyle \: x({x}^{} + 1)- 5x- 5 = 0[/tex]

factor out -5:

[tex] \displaystyle \: x({x}^{} + 1)- 5(x + 1 )= 0[/tex]

group:

[tex] \displaystyle \: (x + 1 )(x - 5)= 0[/tex]

hence our answer is B

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