contestada

Tom's mass is 70.0 kg, and Sam's
mass is 50.0 kg. Tom and Sam are
standing 20.0 m apart on the dance
floor. Sam looks up and sees Tom.
Sam feels an attraction. Supposing
that the attraction is gravitational,
find its size. Assume that both Tom
and Sam can be replaced by
spherical masses.
5.84Å~10−10 N

Respuesta :

Answer:

5.84×10^-10 N

Explanation:

F=G×ms×mr/r^2

ms=50 kg

mr= 70 kg

r=20 m

F=6.67×10^-11 N×m^2/kg^2×50 kg×70 kg/(20 m)^2

F=5.84×10^-10 N

The gravitational force is [tex]5.84*10^{-10} N[/tex].

What is force of gravitation?

The gravitational force is a force that attracts any two objects with mass.

[tex]F=G{\frac{m_1m_2}{r^2}}[/tex]

Where,

F = force

G = gravitational constant

[tex]m_{1}[/tex] = mass of object 1

[tex]m_{2}[/tex] = mass of object 2

r = distance between centers of the masses

[tex]m_{1}[/tex] =      70kg

[tex]m_{2}[/tex] = 50kg

r       =      20 m

G     =       [tex]6.67*10^{-11} Nm^2/kg^2[/tex]

[tex]F= \frac{6.67*10^{-11}*70*50}{20^2}[/tex]

[tex]F = 5.84*10^{-10} N[/tex]

To learn more about Gravitational force here

https://brainly.com/question/12528243

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