Answer:
13. PS = 21.37
14. 68.74°
Step-by-step explanation:
13. QS/39 = tan 28
QS = 39 tan 28
sin 76 = QS/PS
PS sin 76 = QS
PS = QS/sin 76
= 39 tan 28/sin 76
= 21.37
14. tan 47 = BD/18
BD = 18 tan 47
cos CDB = 7/BD
= 7/(18 tan 47)
m∠CDB = arccos [7/(18 tan 47)
= arccos .362644...
= 68.74°
The trigonometry we get PS = 21.37 and m∠CDB= 68.74°
Trigonometry finding sides and angles
We have to find
The value of tan is opposite side/adjacent side
Therefore we get
13. QS/39 = tan 28
QS = 39 tan 28
sin 76 = QS/PS
PS sin 76 = QS
PS = QS/sin 76
PS = 39 tan 28/sin 76
PS = 21.37
14. tan 47 = BD/18
BD = 18 tan 47
cos CDB = 7/BD
cos CDB= 7/(18 tan 47)
m∠CDB = arccos [7/(18 tan 47)
m∠CDB = arccos .362644...
m∠CDB = 68.74°
To learn more about the trigonometry visit:
https://brainly.com/question/24349828
