Answer:
0.156 M
Explanation:
The computation of the molarity of the acetic acid solution is shown below:
The balanced chemical reaction is
[tex]KOH + CH_3COOH -->CH_3COOK + H_2O[/tex]
As we know that The KOH and acetic acid would have 1:1 ratio. Here we need to determine the moles of KOH
So,
moles KOH = 0.0155 L ×0.214 mol/L
= 3.317x10-3 mol
Now moles CH_3COOH = 3.317x10-3 mol
[CH3COOH] = moles ÷ volume
= 3.317 × 10^-3 mol ÷ 0.0212 L
= 0.156 M
