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Express the height of the tower in terms of trigonometric ratios. A) 35(cos95°) B) 95(tan35°) C) 95(cot35°) D) 95(sin35°)

Respuesta :

abidemiokin

Answer:

95tan35°

Step-by-step explanation:

Find the diagram attached

Given the following

Adjacent = 95m

Opposite = height of the tower

Angle of elevation  = 35degrees

Using SOH CAH TOA

tan theta = opp/adj

Tan 35 = h/95

Cross multiply

95 * tan 35 = h

95tan35 = h

Swap

h = 95tan35

Hence then the height of the tower in terms of trigonometric ratios is 95tan35°

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