Respuesta :
Answer:
62 grams
Explanation:
Molarity=mol/liter
We have mL and Molarity
500 mL * 1 L/1000 mL=0.5
Plug 0.5 in and solve for moles
0.75=mol/0.5
0.75*0.5=0.375 mol
Convert to grams by finding the mass of KI: 39+126.9= 165.9 grams
0.375 mol KI * 165.9 grams KI/1 mol KI= 62.2125 grams
The mass of KI needed is 124.5 grams, this can be calculated by adding the values in molarity formula.
What is Molarity?
It is defined as number of moles of solute over volume of solution in liters.
It is given by:
M = n/ V
What information do we have?
Molarity= 0.750 M
Volume = 500 mL= 1 L
Molar mass of KI = 166 g/mol
To find:
Mass of KI=?
On substituting the values:
M= n/V
0.750 M= n/ 1 L
n= 0.750 M* 1l
n= 0.750 moles
Number of moles is the ratio between mass and molar mass.
n= m/M
0.750 moles = m/ 166 g/mol
m= 0.750*166
m= 124.5 grams.
Thus, the mass of KI needed is 124.5 grams.
Find more information about Molarity here:
brainly.com/question/17138838