contestada

1. The nearest distance of distinct vision of
a hypermetropial person is 60 cm. If this
distance is reduced by 20 cm by using
spectacles. What is the nature and focal
length of the lens?
a. +30 cm b. +35 cm
-30 cm
d. -40 cm
c.​

Respuesta :

Answer:

The focal length of the lens is +30 and it is a convex lens.

Explanation:

Given that,

The nearest distance of distinct vision of  a hypermetropial person is 60 cm, v = -60 cm

The distance is reduced by 20 cm, u = -20 cm

We need to find the nature and focal length of the lens.

Let f be the focal length of the lens. Using lens formula,

[tex]\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}\\\\\dfrac{1}{f}=\dfrac{1}{(-60)}-\dfrac{1}{(-20)}\\\\f=+30\ cm[/tex]

So, the focal length of the lens is +30 and it is a convex lens.

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