Answer:
n₂ = 1.459
Explanation:
This is a refraction exercise
n₁ sin θ₁ = n₂ sin θ₂
where n₁ and n₂ are the refractive indices of the incident and refracted medium, respectively
In the exercise they indicate that the incident medium is the air that has a refractive index n1 = 1
n₂ = n₁ [tex]\frac{sin \ \theta_1 }{sin\ \theta_2 }[/tex]
let's calculate
n₂ = 1 [tex]\frac{ sin \ 45}{sin \ 29}[/tex]
n₂ = 1.459
The absolute index of refraction of the medium X in which the monochromatic ray of light enters from air is 1.459.
According to the Snell's law, the ratio of index of reflection of the different material is equal to the ratio of incident sine angle and reflective sine angle. It can be given as,
[tex]\dfrac{n_1}{n_2}=\dfrac{\sin\theta_2}{\sin\theta_1}[/tex]
Here (n₁ and n₂) are the index and reflective index and (θ₁ and θ₂) are the incident and reflected angle.
A monochromatic ray of light (f = 5.09 x 1014 Hz) travels from air into medium X.
The angle of incidence of the ray in air is 45.0° and the ray's angle of refraction in medium X is 29.0°.
As, it is known that the index of reflection of air is 1. Thus, by the Snell's law, the absolute index of refraction of medium X is,
[tex]\dfrac{1}{n_x}=\dfrac{\sin(29)}{\sin(45)}\\n_x=1.459[/tex]
Thus, the absolute index of refraction of the medium X in which the monochromatic ray of light enters from air is 1.459.
Learn more about the Snell's law here;
https://brainly.com/question/10112549
