Answer:
mi = 31.28 g
Explanation:
According to the law of conservation of energy:
[tex]Heat\ Gain\ by\ Ice = Heat\ Lost\ by\ Water\\m_iL = m_wC\Delta T\\[/tex]
where,
mi = mass of ice = ?
L = Latent heat of fusion of ice = 334 J/g
mw = mass of water = 50 g
C = specific heat of water = 4.18 J/g.°C
ΔT = change in temperature of water = 75°C - 25°C = 50°C
Therefore,
[tex]m_i(334\J/g) = (50\ g)(4.18\ J/g.^oC)(50^oC)[/tex]
mi = 31.28 g
