The stone will hit the ground after 3.5 seconds.
Given information:
A stone is dropped from a 196-foot platform.
The height of the stone after t seconds is represented by [tex]h=-16t^2+v_0t+196[/tex]
As the stone hits the ground, the height will become zero and the initial velocity [tex]v_0[/tex] is equal to zero as it is dropped.
So, the time after which the stone will hit the ground will be calculated as,
[tex]h=-16t^2+v_0t+196\\0=-16t^2+0t+196\\16t^2=196\\t^2=12.25\\t=3.5[/tex]
Therefore, the stone will hit the ground after 3.5 seconds.
For more details, refer to the link:
https://brainly.com/question/13418564
