Answer:
[tex]n_{Cl_2}=0.3molCl_2[/tex]
Explanation:
Hello there!
In this case, according to the given chemical reaction whereas the sodium chloride is in a 2:1 mole ratio with chlorine, the required moles of the later are computed as shown below:
[tex]n_{Cl_2}=0.6molNaCl*\frac{1molCl_2}{2molNaCl}[/tex]
So we cancel out the moles of NaCl to obtain:
[tex]n_{Cl_2}=0.3molCl_2[/tex]
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