Answer:
8.33 L .
Explanation:
Hello there!
In this case, according to the given problem, it is possible to firstly write up the undergoing chemical reaction:
[tex]3H_2+N_2\rightarrow 2NH_3[/tex]
Whereas the mole ratio of hydrogen to nitrogen is 3:1. In such a way, given that the mole ratios can be also applied in volume when the temperature and pressure remain unchanged, it is possible to compute the required volume of nitrogen from 25.0 L of hydrogen as shown below:
[tex]25.0L\ H_2*\frac{1L \ N_2}{3L\ H_2}\\\\=8.33L[/tex]
Best regards!