6. A piece of solid gold was heated from 274K to 314K. 35.73 of energy was needed to raise the temperature.
What mass of gold was present?

Respuesta :

From Q = mcΔT, we can rearrange the equation to solve for mass, m = Q/cΔT. The specific heat capacity, c, of solid gold is 0.129 J/g °C. I'm assuming that the energy is given in joules, as it's not specified in the question as written.

m = Q/cΔT = (35.73 J)/(0.129 J/g °C)(40.85 °C - 0.85°C)

m = 6.92 g of gold was present  

The heat of the substance depends on the mass, specific heat, and temperature change of the system. The mass of gold that was present was, 6.92 g.

What is mass?

Mass of the substance in the thermodynamic system is the ratio of the heat to the product of the specific heat and the temperature change. It is given as,

[tex]\rm m = \rm \dfrac{Q}{c \Delta T}[/tex]

Given,

Heat (Q) = 35.73 J

Specific heat (c) = 0.129 J/g °C

Temperature change = 40 degrees celsius

Mass of gold is calculated as:

35.73 ÷ (0.129) (40) = 6.92 gm

Therefore, 6.92 gms of gold is present.

Learn more about mass here:

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