Answer: [tex]33,007.9\ ft[/tex]
Step-by-step explanation:
Given
The plane is cruising at an altitude of [tex]h=10,200\ ft[/tex]
The angle of depression is [tex]\theta=18^{\circ}[/tex]
Suppose the distance of the plane to the runway is x
from figure
[tex]\Rightarrow \sin 18^{\circ}=\dfrac{h}{x}\\\\\Rightarrow \sin 18^{\circ}=\dfrac{10,200}{x}\\\\\Rightarrow x=33,007.9\ ft[/tex]
