Respuesta :
Answer:
The solution is given below:
Step-by-step explanation:
The computation of the area of the horizontal cross section of the cyclinder is given below:
In the case when it is a circle
The area of the circle is
= πr^2
= 3.14 × (2.75 ÷ 2)^2
= 11.873 inches^2
In the case when it is a rectangle
The area of the rectangle is
= 6 × 2.75
= 16.5 inches^2
Hence, the above show the calculations
The area of the horizontal cross section.
When circular is [tex]11.873 inches^2[/tex]
When it is rectangular [tex]16.5inches^2[/tex]
The computation of the area of the horizontal cross section of the cylinder
What is the formula of the area of the circle?
The area of the circle is[tex]=\pi r^{2}[/tex]
use the given value in above formula we get,
[tex]= 3.14 \times (\frac{2.75}{2} )^2[/tex]
[tex]= 11.873 inches^2[/tex]
when it is a rectangle then the area of the rectangle is
[tex]= 6 \times 2.75[/tex]
[tex]= 16.5 inches^2[/tex]
Therefore,the area of the horizontal cross section.
when circular is [tex]11.873 inches^2[/tex]
When it is rectangular [tex]16.5inches^2[/tex]
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